Answer :
The equation of a hyperbola with directrices at x = ±2 and foci at (6, 0) and (−6, 0) is y squared over 48 minus x squared over 12 equals 1.
What is the equation of hyperbola?
The equation of the hyperbola is the equation which is used to represent the hyperbola in the algebraic equation form, with the value of center point in the coordinate plane and foci.
The standard form of the equation of the hyperbola can be given as,
[tex]\dfrac{(y-k)^2}{b^2}-\dfrac{(x-h)^2}{a^2}=r^2[/tex]
Here (h,k) is the center of the hyperbola, (b) is the transverse axis, and (a) is the conjugate axis.
The foci of the hyperbola is,
[tex](h,k\pm c)[/tex]
The directrix is,
[tex]y=k\pm \dfrac{a^2}{c}[/tex]
A hyperbola is given with directrices at x = ±2 and foci at (6, 0) and (−6, 0). Thus, the directrix is,
[tex]y=k\pm \dfrac{a^2}{c}\\\pm 2=k\pm \dfrac{a^2}{c}\\\dfrac{a^2}{6}=2\\a^2=12\\[/tex]
It is known that,
[tex]a^2+b^2=c^2\\[/tex]
Put the value of a and c,
[tex](12)+b^2=6^2\\b^2=36-12\\b^2=24[/tex]
The value of center is (0,0). Thus, the equation of hyperbola is,
[tex]\dfrac{(y-0)^2}{24^2}-\dfrac{(x-0)^2}{12^2}=1\\\dfrac{y^2}{24^2}-\dfrac{x^2}{12^2}=1[/tex]
Thus, the equation of a hyperbola with directrices at x = ±2 and foci at (6, 0) and (−6, 0) is y squared over 48 minus x squared over 12 equals 1.
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